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A bar magnet when placed at an angle of ...

A bar magnet when placed at an angle of `30^(@)` to the direction of magnetic field induction of `5xx10^(-2)T`, experiences a moment of couple `25xx10^(-6) N-m`. If the length of the magnet is 5cm its pole strength is

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To solve the problem step by step, we will use the information provided and apply the relevant formulas. ### Step 1: Understanding the Given Data We are given: - Angle (θ) = 30° - Magnetic field induction (B) = 5 x 10^(-2) T - Moment of couple (Torque, τ) = 25 x 10^(-6) N·m - Length of the magnet (L) = 5 cm = 5 x 10^(-2) m ### Step 2: Using the Torque Formula The torque (τ) acting on a magnetic dipole in a magnetic field is given by the formula: \[ \tau = mB \sin \theta \] Where: - m = magnetic moment - B = magnetic field strength - θ = angle between the magnetic moment and the magnetic field ### Step 3: Substitute the Known Values We can rearrange the formula to solve for the magnetic moment (m): \[ m = \frac{\tau}{B \sin \theta} \] Substituting the known values: - τ = 25 x 10^(-6) N·m - B = 5 x 10^(-2) T - sin(30°) = 0.5 Now substituting these values into the equation: \[ m = \frac{25 \times 10^{-6}}{(5 \times 10^{-2}) \times 0.5} \] ### Step 4: Calculate the Magnetic Moment Calculating the denominator: \[ (5 \times 10^{-2}) \times 0.5 = 2.5 \times 10^{-2} \] Now substituting this back into the equation for m: \[ m = \frac{25 \times 10^{-6}}{2.5 \times 10^{-2}} = 1 \times 10^{-3} \text{ A·m}^2 \] ### Step 5: Relating Magnetic Moment to Pole Strength The magnetic moment (m) is also related to the pole strength (p) and length (L) of the magnet by the formula: \[ m = p \times L \] We can rearrange this to find the pole strength (p): \[ p = \frac{m}{L} \] ### Step 6: Substitute the Values to Find Pole Strength Substituting the values we have: - m = 1 x 10^(-3) A·m² - L = 5 x 10^(-2) m Now substituting these into the equation for p: \[ p = \frac{1 \times 10^{-3}}{5 \times 10^{-2}} = 0.2 \times 10^{-1} = 2 \times 10^{-2} \text{ A·m} \] ### Final Answer The pole strength of the bar magnet is: \[ p = 2 \times 10^{-2} \text{ A·m} \] ---

To solve the problem step by step, we will use the information provided and apply the relevant formulas. ### Step 1: Understanding the Given Data We are given: - Angle (θ) = 30° - Magnetic field induction (B) = 5 x 10^(-2) T - Moment of couple (Torque, τ) = 25 x 10^(-6) N·m - Length of the magnet (L) = 5 cm = 5 x 10^(-2) m ...
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