The magnetic moment produced in a substance of `1 gm is 6xx10^(-7) "ampere","metre"^(2)`. If its density is `5 gm//cm^(3)`, then the intensity of magnetisation in `A//m` will be

Explanation

To find the intensity of magnetization (I) in a substance, we can use the formula:

\[ I = \frac{M}{V} \]

where \( M \) is the magnetic moment and \( V \) is the volume of the substance.

### Step 1: Identify the given values
- Magnetic moment \( M = 6 \times 10^{-7} \, \text{A m}^2 \)
- Mass \( m = 1 \, \text{g} = 1 \times 10^{-3} \, \text{kg} \) (since \( 1 \, \text{g} = 10^{-3} \, \text{kg} \))
- Density \( \rho = 5 \, \text{g/cm}^3 = 5 \times 10^{3} \, \text{kg/m}^3 \) (since \( 1 \, \text{g/cm}^3 = 1000 \, \text{kg/m}^3 \))

### Step 2: Calculate the volume of the substance
Using the formula for volume:

\[ V = \frac{m}{\rho} \]

Substituting the values:

\[ V = \frac{1 \times 10^{-3} \, \text{kg}}{5 \times 10^{3} \, \text{kg/m}^3} \]

Calculating the volume:

\[ V = \frac{1 \times 10^{-3}}{5 \times 10^{3}} = \frac{1}{5 \times 10^{6}} = 2 \times 10^{-7} \, \text{m}^3 \]

### Step 3: Calculate the intensity of magnetization
Now substitute \( M \) and \( V \) into the formula for intensity of magnetization:

\[ I = \frac{M}{V} = \frac{6 \times 10^{-7} \, \text{A m}^2}{2 \times 10^{-7} \, \text{m}^3} \]

Calculating \( I \):

\[ I = \frac{6}{2} = 3 \, \text{A/m} \]

### Final Answer
The intensity of magnetization is \( 3 \, \text{A/m} \).

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