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The plane of dip circle is set in the ge...

The plane of dip circle is set in the geographic meridian and the apparent dip is `theta_(1)`. It is then set in a vertical plane perpendicular to the geographic meridian. Now, the apparent dip is `theta_(2)`. The angle of declination `theta` at that place is

A

`theta=tan^(-1)(tan delta_(1) tan delta_(2))`

B

`theta=tan^(-1)(tan delta_(1)+tan delta_(2))`

C

`theta=tan^(-1)(tan delta_(1)/tan delta_(2))`

D

`theta=tan^(-1)(tan delta_(1)-tan delta_(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
`Here, tandelta_(1)=(V)/(Hcostheta)`

`tan delta_(2)=(V)/(H cos (90^(@)-theta))=(V)/(H sin theta)`
`tan delta_(2)/(tan delta_(2))=(sin theta)/(sin theta)=tan theta`
`theta=tan^(-1)((tan delta_(1))/(tan delta_(2)))`
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