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Two short magnets of magnetic moment 100...

Two short magnets of magnetic moment `1000 Am^(2)` are placed as shown at the corners of a square of side `10 cm`. The net magnetic induction at P is

A

0.1T

B

0.2T

C

0.3T

D

0.4T

Text Solution

Verified by Experts

The correct Answer is:
A
Point P lies on equatorial line of magnet (1) and axial line of magnet (2) as shown

`B_(1)=(mu_(0))/(4pi).(M)/(d^(3))=10^(-7)xx(1000)/(0.1)^(3)=0.1T`
`B_(2)=(mu_(0))/(4pi).(2M)/(d^(3))=10^(-7)xx(2xx1000)/(0.1)^(3)=0.2T`
`therefore B_("net")=-B_(2)-B_(1)=0.1T`
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Knowledge Check

  • Two short bar magnets of magnetic moments m each are arranged at the opposite corners of a square of side d such that their centres coincide with thecorners and their axes are parallel. If the like poles are in the same direction, the magnetic induction at any of the other corners of the square is

    A
    `(mu_(0))/(4pi)(m)/(d^(3))`
    B
    `(mu_(0))/(4pi)(2m)/(d^(3))`
    C
    `(mu_(0))/(4pi)(m)/(2d^(3))`
    D
    `(mu_(0))/(4pi)(m^(3))/(2d^(3))`

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