The vertical component of earth's magnetic field at a place is `sqrt3` times the horizontal component the value of angle of dip at this place is

Options

A. `60^(@)`
B. `30^(@)`
C. `45^(@)`
D. `0^(@)`

Explanation

To solve the problem, we need to determine the angle of dip (θ) given that the vertical component (V) of the Earth's magnetic field is √3 times the horizontal component (H).

### Step-by-Step Solution:

1. **Understanding the Components**:
- Let the horizontal component of the Earth's magnetic field be \( H \).
- The vertical component is given as \( V = \sqrt{3} H \).

2. **Using the Formula for Angle of Dip**:
- The angle of dip (θ) is related to the vertical and horizontal components of the Earth's magnetic field by the formula:
\[ \tan(\theta) = \frac{V}{H} \]

3. **Substituting the Values**:
- Substitute the expression for the vertical component into the formula:
\[ \tan(\theta) = \frac{\sqrt{3} H}{H} \]
- Simplifying this gives:
\[ \tan(\theta) = \sqrt{3} \]

4. **Finding the Angle**:
- To find θ, we need to determine the angle whose tangent is √3. We know from trigonometric values that:
\[ \tan(60^\circ) = \sqrt{3} \]
- Therefore, we can conclude:
\[ \theta = 60^\circ \]

5. **Final Answer**:
- The angle of dip at this place is \( 60^\circ \).