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A short magnet of magnetic induction fie...

A short magnet of magnetic induction fields `B_(1),B_(2),B_(3)` values on this line at points which are at distance 30cm, 60cm and 90cm respectivley from the centre of the magnet is

A

`27:3:37:1`

B

`37.3:1:27`

C

`27:8:3.37`

D

`1:2:3`

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To find the ratio of the magnetic induction fields \( B_1, B_2, \) and \( B_3 \) at distances \( r_1 = 30 \, \text{cm}, r_2 = 60 \, \text{cm}, \) and \( r_3 = 90 \, \text{cm} \) from the center of a short magnet, we can follow these steps: ### Step 1: Convert distances from centimeters to meters We need to convert the distances from centimeters to meters: - \( r_1 = 30 \, \text{cm} = 0.3 \, \text{m} \) - \( r_2 = 60 \, \text{cm} = 0.6 \, \text{m} \) - \( r_3 = 90 \, \text{cm} = 0.9 \, \text{m} \) ### Step 2: Write the formula for magnetic induction The magnetic induction \( B \) at a distance \( r \) from a short magnet is given by the formula: \[ B = \frac{\mu_0}{4\pi} \cdot \frac{m}{r^3} \] where \( m \) is the magnetic moment of the magnet and \( \mu_0 \) is the permeability of free space. ### Step 3: Establish the ratios for \( B_1, B_2, \) and \( B_3 \) Since \( m \) and \( \mu_0 \) are constants for all three distances, we can express the ratios as: \[ \frac{B_1}{B_2} = \frac{r_2^3}{r_1^3}, \quad \frac{B_2}{B_3} = \frac{r_3^3}{r_2^3}, \quad \frac{B_1}{B_3} = \frac{r_3^3}{r_1^3} \] Thus, we can write: \[ \frac{B_1}{B_2} : \frac{B_2}{B_3} : \frac{B_1}{B_3} = \frac{1}{r_1^3} : \frac{1}{r_2^3} : \frac{1}{r_3^3} \] ### Step 4: Calculate \( r_1^3, r_2^3, \) and \( r_3^3 \) Now we calculate the cubes: - \( r_1^3 = (0.3)^3 = 0.027 \, \text{m}^3 \) - \( r_2^3 = (0.6)^3 = 0.216 \, \text{m}^3 \) - \( r_3^3 = (0.9)^3 = 0.729 \, \text{m}^3 \) ### Step 5: Write the ratios Now we can express the ratios: \[ \frac{B_1}{B_2} : \frac{B_2}{B_3} : \frac{B_1}{B_3} = \frac{1}{0.027} : \frac{1}{0.216} : \frac{1}{0.729} \] ### Step 6: Simplify the ratios To simplify, we can take the common denominator (which is \( 729 \)): - For \( B_1 \): \( \frac{729}{0.027} = 27000 \) - For \( B_2 \): \( \frac{729}{0.216} = 3375 \) - For \( B_3 \): \( \frac{729}{0.729} = 1 \) Thus, the ratio becomes: \[ 27000 : 3375 : 1 \] ### Step 7: Reduce the ratio Dividing each term by 1 gives: \[ 27000 : 3375 : 1 \] This can be further simplified to: \[ 8 : 1 : \frac{1}{27} \] ### Final Ratio Thus, the final ratio of \( B_1 : B_2 : B_3 \) is: \[ 27 : 3.375 : 1 \]

To find the ratio of the magnetic induction fields \( B_1, B_2, \) and \( B_3 \) at distances \( r_1 = 30 \, \text{cm}, r_2 = 60 \, \text{cm}, \) and \( r_3 = 90 \, \text{cm} \) from the center of a short magnet, we can follow these steps: ### Step 1: Convert distances from centimeters to meters We need to convert the distances from centimeters to meters: - \( r_1 = 30 \, \text{cm} = 0.3 \, \text{m} \) - \( r_2 = 60 \, \text{cm} = 0.6 \, \text{m} \) - \( r_3 = 90 \, \text{cm} = 0.9 \, \text{m} \) ...
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