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A series L-C-R circuit containing a resi...

A series `L-C-R` circuit containing a resistance of `120Omega` has resonance frequency `4xx10^5rad//s`. At resonance the voltages across resistance and inductance are `60V` and `40V`, respectively. Find the values of `L` and `C`.At what angular frequency the current in the circuit lags the voltage by `pi//4`?

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To solve the problem step by step, we will find the values of inductance \( L \) and capacitance \( C \) in the given series \( L-C-R \) circuit, and then determine the angular frequency at which the current lags the voltage by \( \frac{\pi}{4} \). ### Step 1: Find the Current in the Circuit We know the voltage across the resistance \( V_R = 60V \) and the resistance \( R = 120 \Omega \). The current \( I \) can be calculated using Ohm's law: \[ I = \frac{V_R}{R} = \frac{60V}{120 \Omega} = \frac{1}{2} A \] ...
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