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A series L-C-R circuit is connected acro...

A series L-C-R circuit is connected across an AC source V = `10sin[100pit - pi/6]`. Current from the supply is I = `2sin[100pit + pi/12]`, What is the average power dissipated?

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To find the average power dissipated in a series L-C-R circuit connected to an AC source, we can follow these steps: ### Step 1: Identify the given quantities - The voltage across the circuit is given by: \[ V = 10 \sin(100\pi t - \frac{\pi}{6}) \] From this, we can identify the peak voltage \( V_0 = 10 \) volts. ...
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