An L-C circuit contains 20 mH inductor and a `50 muF` capacitor with an initial charge of 10 mC. The resistance of the circuit is negligible. Let the instant the circuit is closed be t = 0. what is the total energy stored initially ? At what times is the total energy shared equally between the inductor and the capacitor ?

Explanation

To solve the problem step by step, we will first calculate the total energy stored initially in the LC circuit and then find the times when the energy is shared equally between the inductor and the capacitor.

### Step 1: Calculate the initial total energy stored in the LC circuit.

The formula for the energy stored in a capacitor is given by:

\[
E = \frac{1}{2} \frac{Q^2}{C}
...