The capacitance of a pure capacitance is `1` farad. In DC circuits, its effective resistance will be

Options

A. zero
B. infinte
C. `1Omega`
D. `1/2Omega`

Explanation

To solve the problem, we need to determine the effective resistance of a pure capacitor in a DC circuit with a capacitance of 1 farad.

### Step-by-Step Solution:

1. **Understanding the Nature of a Capacitor in DC Circuits:**
- In a DC circuit, a capacitor initially allows current to flow when it is charging. Once fully charged, it blocks any further current flow. Therefore, after a certain time, the capacitor behaves like an open circuit.

**Hint:** Remember that in a DC circuit, after charging, a capacitor does not allow current to pass through.

2. **Capacitive Reactance Formula:**
- The capacitive reactance (X_C) of a capacitor is given by the formula:
\[ X_C = \frac{1}{\omega C} \]
where \( \omega = 2\pi f \) (angular frequency) and \( C \) is the capacitance.

**Hint:** Recall that reactance depends on frequency and capacitance.

3. **Frequency in DC Circuits:**
- In a DC circuit, the frequency \( f \) is 0 Hz. Therefore, the angular frequency \( \omega \) also becomes 0:
\[ \omega = 2\pi \times 0 = 0 \]

**Hint:** Consider what happens to the frequency in a DC circuit.

4. **Calculating Capacitive Reactance:**
- Substituting \( \omega = 0 \) into the capacitive reactance formula:
\[ X_C = \frac{1}{0} \]
- Since division by zero is undefined, we conclude that:
\[ X_C \rightarrow \infty \]

**Hint:** Think about the implications of division by zero in physics.

5. **Effective Resistance in DC Circuits:**
- Since the capacitive reactance is infinite, the effective resistance of the capacitor in a DC circuit is also considered to be infinite. This means that no current flows through the capacitor once it is fully charged.

**Hint:** Relate the concept of infinite reactance to the idea of resistance in the circuit.

### Final Answer:
The effective resistance of a pure capacitor with a capacitance of 1 farad in a DC circuit is **infinite**.