If an `8Omega` resistance and `6Omega` reactance are present in an AC series circuit then the impedence of the circuit will be

Options

A. `2Omega`
B. `14Omega`
C. `4Omega`
D. `10Omega`

Explanation

To find the impedance of an AC series circuit with a given resistance and reactance, we can use the formula for impedance \( Z \):

\[ Z = \sqrt{R^2 + X^2} \]

Where:
- \( R \) is the resistance (in ohms)
- \( X \) is the reactance (in ohms)

### Step-by-Step Solution:

1. **Identify the given values**:
- Resistance \( R = 8 \, \Omega \)
- Reactance \( X = 6 \, \Omega \)

2. **Substitute the values into the impedance formula**:
\[ Z = \sqrt{R^2 + X^2} = \sqrt{8^2 + 6^2} \]

3. **Calculate \( R^2 \) and \( X^2 \)**:
- \( R^2 = 8^2 = 64 \)
- \( X^2 = 6^2 = 36 \)

4. **Add \( R^2 \) and \( X^2 \)**:
\[ R^2 + X^2 = 64 + 36 = 100 \]

5. **Take the square root**:
\[ Z = \sqrt{100} = 10 \, \Omega \]

6. **Conclusion**:
The impedance of the circuit is \( Z = 10 \, \Omega \).

### Final Answer:
The impedance of the circuit is \( 10 \, \Omega \).

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