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In a transformer, the number of turns in...

In a transformer, the number of turns in primary and secondary are `500` and `2000` respectively. If current in primary is `48A`, the current in the secondary is

A

12A

B

24 A

C

48 A

D

144 A

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To find the current in the secondary coil of a transformer given the number of turns in the primary and secondary coils and the current in the primary coil, we can use the transformer equations. Here’s the step-by-step solution: ### Step 1: Write down the transformer equations In a transformer, the relationship between the primary and secondary coils can be expressed as: \[ \frac{E_S}{E_P} = \frac{N_S}{N_P} = \frac{I_P}{I_S} \] where: - \(E_S\) = voltage in the secondary - \(E_P\) = voltage in the primary - \(N_S\) = number of turns in the secondary - \(N_P\) = number of turns in the primary - \(I_P\) = current in the primary - \(I_S\) = current in the secondary ### Step 2: Substitute the known values Given: - \(N_P = 500\) - \(N_S = 2000\) - \(I_P = 48 \, A\) We can substitute these values into the equation: \[ \frac{N_S}{N_P} = \frac{I_P}{I_S} \] This becomes: \[ \frac{2000}{500} = \frac{48}{I_S} \] ### Step 3: Simplify the ratio Now, simplify the left side: \[ \frac{2000}{500} = 4 \] So, we have: \[ 4 = \frac{48}{I_S} \] ### Step 4: Solve for \(I_S\) To find \(I_S\), we can rearrange the equation: \[ I_S = \frac{48}{4} \] Calculating this gives: \[ I_S = 12 \, A \] ### Final Answer The current in the secondary coil is: \[ I_S = 12 \, A \] ---
To find the current in the secondary coil of a transformer given the number of turns in the primary and secondary coils and the current in the primary coil, we can use the transformer equations. Here’s the step-by-step solution: ### Step 1: Write down the transformer equations In a transformer, the relationship between the primary and secondary coils can be expressed as: \[ \frac{E_S}{E_P} = \frac{N_S}{N_P} = \frac{I_P}{I_S} \] where: ...
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