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The output current versus time curve of ...

The output current versus time curve of a rectifier is shown in the figure. The average value of output current in this case is

A

0

B

`I_(O)/2`

C

`(2I_(0))/(pi)`

D

`I_(0)`

Text Solution

Verified by Experts

The correct Answer is:
C
c) Average value of output current is given by
`I_(av)` = `I_(av) = (int_(0)^(T//2)Idt)/(int_(0)^(T//2)dt)= (int_(0)^(T//2)I_(0)sinomegatdt)/(T//2)`
`=(2I_(0))/T[-(cosomegat)/(omega)]_(0)^(T//2)`
`=(2I_(0))/T[-(cos(omegaT//2)/(omega)+(cos0^(@))/(omega))]`
`=(2I_(0))/(omegaT)[(-cospi+cos0^(@))]=(2I_(0))/(2pi)[1+1]=(2I_(0))/(pi)`
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