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In a transformer, number of turns in the...

In a transformer, number of turns in the primary coil are 140 and that in the secondry coil are 280. If current i primary ciol is 4A, then that in the secondary coil is

A

4A

B

2A

C

6A

D

10A

Text Solution

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The correct Answer is:
To solve the problem step by step, we can use the transformer equations. ### Step 1: Understand the transformer relationship In a transformer, the relationship between the primary and secondary coils can be expressed using the formula: \[ \frac{N_s}{N_p} = \frac{I_p}{I_s} \] where: - \(N_s\) = number of turns in the secondary coil - \(N_p\) = number of turns in the primary coil - \(I_p\) = current in the primary coil - \(I_s\) = current in the secondary coil ### Step 2: Identify the given values From the problem, we have: - \(N_p = 140\) turns (primary coil) - \(N_s = 280\) turns (secondary coil) - \(I_p = 4\) A (current in the primary coil) ### Step 3: Substitute the values into the transformer equation We can substitute the known values into the transformer equation: \[ \frac{280}{140} = \frac{4}{I_s} \] ### Step 4: Simplify the equation Now, simplify the left side: \[ \frac{280}{140} = 2 \] So, the equation becomes: \[ 2 = \frac{4}{I_s} \] ### Step 5: Solve for \(I_s\) To find \(I_s\), we can rearrange the equation: \[ I_s = \frac{4}{2} \] Calculating this gives: \[ I_s = 2 \text{ A} \] ### Final Answer The current in the secondary coil is \(2\) A. ---
To solve the problem step by step, we can use the transformer equations. ### Step 1: Understand the transformer relationship In a transformer, the relationship between the primary and secondary coils can be expressed using the formula: \[ \frac{N_s}{N_p} = \frac{I_p}{I_s} \] where: ...
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