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A 50 Hz AC source of 20 V is connected a...

A `50 Hz AC` source of `20 V` is connected across `R ` and `C` as shown in figureure.

The voltage across `R` is `12 V`. The voltage across `C` is

A

8 V

B

16 V

C

10 V

D

not possible to determine unless value of R and C are given

Text Solution

Verified by Experts

The correct Answer is:
B
`V_(C) = sqrt(V^(2)-V_(R)^(2)) =16 V`
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