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In series LCR circuit voltage drop acros...

In series LCR circuit voltage drop across resistance is 8V, across inductor is 6V and across capacitor is 12V. Then

A

voltage of the source will be leading in the circuit

B

voltage drop across each element will be less than the applied voltage

C

Power factor of the circuit will be `3//4`

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
D
Since, `V_(C) gt V_(L)`
`therefore` X_(C) gt X_(L)`
Hence, current will lead the voltage .
V = `sqrt (V^(2) + V_(C) - V_(L))^(2)= 10 V lt V_(C)`
cos `phi` = `R/Z = 8/10 = 4/5`
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