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In the circuit below, the AC source the ...

In the circuit below, the `AC` source the voltage `V=20cos (omegat)` volts with `omega=2000rad//sec`. The amplitude of the current will be nearest to

A

`2.0A`

B

3.3 A

C

2`sqrt 5` A

D

`sqrt 5` A

Text Solution

Verified by Experts

The correct Answer is:
A
Total resistance of the circiut,
R = 6 + 4 = `10 Omega`
Capacitive reactance,
`X_C= 1 /omegaC = 1 / 2000 xx 50 xx 10^(-6)` = `10 Omega`
Inductive reactance,
`X_L` = `omega`L = ` 2000 xx 5 xx 10^(-3)` = `10 Omega`
`therefore` Z = `sqrt R^(2) + (X_L - X_C)^(2)` = 10`Omega`
Amplitude of current , `I_0` = `V_0/Z = 20/10 = 2A`.
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