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An Ac voltage V=V0 sin 100t is applied t...

An Ac voltage `V=V_0 sin 100t` is applied to the circuit, the phase difference between current and voltage is found to be `pi/4`, then
.

A

R = 100 `Omega`, C= `mu`F

B

R = 1k`Omega` , C = `1mu`F

C

R = 10k`Omega` , L = `H

D

R = 1 k`Omega` , L = 10H.

Text Solution

Verified by Experts

The correct Answer is:
B

In the given graph current is leading the voltage by `45^(@)`. Therefore circuit is C-R.
tan`phi` = `X_C / R` and `phi = pi/4`
`therefore X_C = R`
`implies omega`CR = 1
`impliesCR = 1 / omega = 1 / 100`
When , R = 1k`Omega` = `10^(3) Omega`, then
`C = 1/10 = 10^(-5)F = 10mu`F.
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