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A step-down transformer has 50 turns on ...

A step-down transformer has 50 turns on secondary and 1000 turns on primary winding. If a transformer is connected to 220 V, 1A C AC source, then what is output current of the transformer ?

A

`1/20 A`

B

20 A

C

100 A

D

0.083333333333333

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the properties of transformers and the relationships between voltage, current, and the number of turns in the primary and secondary coils. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Number of turns in the primary coil (N_p) = 1000 turns - Number of turns in the secondary coil (N_s) = 50 turns - Voltage in the primary coil (V_p) = 220 V - Current in the primary coil (I_p) = 1 A 2. **Use the Transformer Equation for Voltage:** The relationship between the primary and secondary voltages and the number of turns is given by: \[ \frac{V_s}{V_p} = \frac{N_s}{N_p} \] Substituting the known values: \[ \frac{V_s}{220} = \frac{50}{1000} \] 3. **Calculate the Secondary Voltage (V_s):** Rearranging the equation to find \(V_s\): \[ V_s = 220 \times \frac{50}{1000} \] \[ V_s = 220 \times 0.05 = 11 \text{ V} \] 4. **Use the Power Conservation Principle:** The power in the primary coil is equal to the power in the secondary coil: \[ V_p \times I_p = V_s \times I_s \] Substituting the known values: \[ 220 \times 1 = 11 \times I_s \] 5. **Calculate the Secondary Current (I_s):** Rearranging the equation to find \(I_s\): \[ I_s = \frac{220}{11} \] \[ I_s = 20 \text{ A} \] ### Final Answer: The output current of the transformer is **20 A**. ---

To solve the problem step by step, we will use the properties of transformers and the relationships between voltage, current, and the number of turns in the primary and secondary coils. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Number of turns in the primary coil (N_p) = 1000 turns - Number of turns in the secondary coil (N_s) = 50 turns - Voltage in the primary coil (V_p) = 220 V ...
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