For a transformer, the turns ratio is 3 and its efficiency is 0.75. The current flowing in the primary coil is 2A and the voltage applied to it is 100 V. Then the voltage and the current flowing in the secondary coild are..............respectively.

Options

A. 150 V, 1.5 A
B. 300 V, 0.5 A
C. 300 V, 1.5 A
D. 150 V, 0.5 A

Explanation

To solve the problem regarding the transformer, we will follow these steps:

### Step 1: Understand the given information
- Turns ratio (Ns/Np) = 3
- Efficiency = 0.75 (not needed for this calculation)
- Current in primary coil (Ip) = 2 A
- Voltage applied to primary coil (Vp) = 100 V

### Step 2: Calculate the secondary voltage (Vs)
Using the turns ratio, we can find the secondary voltage using the formula:
\[ \frac{Vs}{Vp} = \frac{Ns}{Np} \]
Rearranging gives:
\[ Vs = Vp \times \frac{Ns}{Np} \]
Substituting the values:
\[ Vs = 100 \, \text{V} \times 3 = 300 \, \text{V} \]

### Step 3: Calculate the secondary current (Is)
Using the relationship between primary and secondary currents, we have:
\[ \frac{Ip}{Is} = \frac{Ns}{Np} \]
Rearranging gives:
\[ Is = Ip \times \frac{Np}{Ns} \]
Since Ns/Np = 3, we have Np/Ns = 1/3. Thus:
\[ Is = 2 \, \text{A} \times \frac{1}{3} = \frac{2}{3} \, \text{A} \approx 0.67 \, \text{A} \]

### Step 4: Finalize the values
The calculated values are:
- Secondary Voltage (Vs) = 300 V
- Secondary Current (Is) = 0.67 A

### Conclusion
The voltage and current flowing in the secondary coil are:
- Vs = 300 V
- Is = 0.67 A