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In R-L-C series circuit, the potential d...

In R-L-C series circuit, the potential difference across each element is 20 V. Now the value of hte resistance alone is doubled, then PD across R, L and C respectively.

A

20 V, 10 V , 10V

B

20 V, 20 V, 20V

C

20 V, 40 V, 40 V

D

10 V, 20 V, 20 V

Text Solution

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The correct Answer is:
To solve the problem step by step, we will analyze the behavior of the R-L-C series circuit when the resistance is doubled. ### Step 1: Understand the Initial Conditions In the given R-L-C series circuit, the potential difference (PD) across each element (R, L, and C) is initially 20 V. This indicates that the circuit is in resonance, where: - \( V_R = V_L = V_C = 20 \, \text{V} \) ### Step 2: Analyze the Effect of Doubling the Resistance When the resistance \( R \) is doubled, the new resistance becomes \( R' = 2R \). ### Step 3: Determine the Current in the Circuit In a series circuit, the current \( I \) is given by: \[ I = \frac{V}{Z} \] Where \( Z \) is the impedance of the circuit. At resonance: \[ Z = R \] Thus, the initial current \( I \) can be expressed as: \[ I = \frac{V}{R} \] Given that \( V = 20 \, \text{V} \), we have: \[ I = \frac{20}{R} \] ### Step 4: Calculate the New Current After Doubling Resistance After doubling the resistance, the new current \( I' \) becomes: \[ I' = \frac{V}{R'} = \frac{V}{2R} = \frac{20}{2R} = \frac{10}{R} \] This shows that the new current is half of the original current: \[ I' = \frac{I}{2} \] ### Step 5: Calculate the New Potential Differences Using Ohm's Law, the potential difference across each component can be calculated: 1. **For the resistor (R)**: \[ V_R' = I' \cdot R' = \frac{10}{R} \cdot 2R = 20 \, \text{V} \] 2. **For the inductor (L)**: Since the circuit is still in resonance, the potential difference across the inductor will equal the potential difference across the capacitor: \[ V_L' = V_C' = \frac{I'}{\omega L} \] But since \( I' = \frac{10}{R} \) and at resonance \( V_L = V_C \): \[ V_L' = V_C' = 10 \, \text{V} \] ### Conclusion After doubling the resistance, the potential differences across the components are: - \( V_R' = 20 \, \text{V} \) - \( V_L' = 10 \, \text{V} \) - \( V_C' = 10 \, \text{V} \) ### Final Answer The potential differences across R, L, and C respectively are: - \( V_R = 20 \, \text{V} \) - \( V_L = 10 \, \text{V} \) - \( V_C = 10 \, \text{V} \)

To solve the problem step by step, we will analyze the behavior of the R-L-C series circuit when the resistance is doubled. ### Step 1: Understand the Initial Conditions In the given R-L-C series circuit, the potential difference (PD) across each element (R, L, and C) is initially 20 V. This indicates that the circuit is in resonance, where: - \( V_R = V_L = V_C = 20 \, \text{V} \) ### Step 2: Analyze the Effect of Doubling the Resistance When the resistance \( R \) is doubled, the new resistance becomes \( R' = 2R \). ...
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