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A transformer of 100 % efficiency has 20...

A transformer of 100 % efficiency has 200 turns in the primary and 40,000 turns in the secondary. It is connected to a 220 V a.c. mains and the secondary feeds to a `100 k Omega` resistance. Calculate the output potential difference per turn and the power delivered to the load.

A

1.1 V

B

25 V

C

18 V

D

11 V

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the transformer equations and the given values. ### Step 1: Understand the Transformer Ratio The transformer ratio relates the primary voltage (Vp), secondary voltage (Vs), primary turns (Np), and secondary turns (Ns) as follows: \[ \frac{V_s}{V_p} = \frac{N_s}{N_p} \] ### Step 2: Substitute the Known Values We know: - \( V_p = 220 \, \text{V} \) - \( N_p = 200 \) - \( N_s = 40000 \) Using the transformer ratio formula, we can express \( V_s \): \[ V_s = V_p \times \frac{N_s}{N_p} \] ### Step 3: Calculate the Secondary Voltage (Vs) Substituting the known values into the equation: \[ V_s = 220 \times \frac{40000}{200} \] Calculating the fraction: \[ \frac{40000}{200} = 200 \] Now substituting this back: \[ V_s = 220 \times 200 = 44000 \, \text{V} \] ### Step 4: Calculate the Output Potential Difference per Turn The potential difference per turn in the secondary coil can be calculated using: \[ \text{Potential difference per turn} = \frac{V_s}{N_s} \] Substituting the values: \[ \text{Potential difference per turn} = \frac{44000}{40000} \] Calculating this gives: \[ \text{Potential difference per turn} = 1.1 \, \text{V} \] ### Step 5: Calculate the Power Delivered to the Load The power delivered to the load (P) can be calculated using: \[ P = \frac{V_s^2}{R} \] Where \( R = 100 \, k\Omega = 100000 \, \Omega \). Substituting the values: \[ P = \frac{(44000)^2}{100000} \] Calculating \( (44000)^2 \): \[ (44000)^2 = 1936000000 \] Now substituting this value: \[ P = \frac{1936000000}{100000} = 19360 \, \text{W} \] ### Final Results - The output potential difference per turn is \( 1.1 \, \text{V} \). - The power delivered to the load is \( 19360 \, \text{W} \).

To solve the problem step by step, we will use the transformer equations and the given values. ### Step 1: Understand the Transformer Ratio The transformer ratio relates the primary voltage (Vp), secondary voltage (Vs), primary turns (Np), and secondary turns (Ns) as follows: \[ \frac{V_s}{V_p} = \frac{N_s}{N_p} \] ...
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