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When an ac source of emfe=E(0) sin (100 ...

When an ac source of emf`e=E_(0) sin (100 t)` is connected across a circuit, the phase difference between emf e and currnet I in the circuit is observed to be `(pi)//(4)` as shown in fig. If the circuit consists possibly only of R-C or R-C of L-R series, find the relationship find the relationship between the two elements.

A

`R= 1kOmega`, C=`10 muF`

B

R=`1kOmega`, `C=1muF`

C

`R=1kOmega`, L=10H

D

`R=1Omega` L=1H

Text Solution

Verified by Experts

The correct Answer is:
C
c) EmF and AC source `E=E_(0)sin(100t)`
We have, `omega=100` and `phi =pi/4=45^(@)`
`tanphi = (omegaL)/R`
`rArr I=(100 xx L)/(R)`
If L=10H, then R=`kOmega`
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