Radiations of intensity `0.5 W//m^(2)` are striking a metal plate. The pressure on the plate is

Options

A. `0.166 xx 10^(-8) Nm^(-2)`
B. `0.332 xx 10^(-8) Nm^(-2)`
C. `0.111 xx 10^(-8) Nm^(-2)`
D. `0.083 xx 10^(-8) Nm^(-2)`

Explanation

To find the pressure exerted on a metal plate by electromagnetic radiation, we can use the formula:

\[ P = \frac{2I}{c} \]

where:
- \( P \) is the pressure,
- \( I \) is the intensity of the radiation,
- \( c \) is the speed of light in vacuum, approximately \( 3 \times 10^8 \, \text{m/s} \).

### Step-by-step Solution:

1. **Identify the given values**:
- Intensity \( I = 0.5 \, \text{W/m}^2 \)
- Speed of light \( c = 3 \times 10^8 \, \text{m/s} \)

2. **Substitute the values into the pressure formula**:
\[ P = \frac{2 \times 0.5}{3 \times 10^8} \]

3. **Calculate the numerator**:
\[ 2 \times 0.5 = 1 \]

4. **Now substitute back into the equation**:
\[ P = \frac{1}{3 \times 10^8} \]

5. **Perform the division**:
\[ P = \frac{1}{3} \times 10^{-8} \, \text{N/m}^2 \]

6. **Calculate \( \frac{1}{3} \)**:
\[ \frac{1}{3} \approx 0.3333 \]

7. **Final pressure calculation**:
\[ P \approx 0.33 \times 10^{-8} \, \text{N/m}^2 \]

### Conclusion:
The pressure on the plate is approximately \( 0.33 \times 10^{-8} \, \text{N/m}^2 \).