The sum delilvers `10^(4) W//m^(2)` of electromagnetic flux to earth's surface. The total power that is incident on a ro of dimensions `(10xx10)m^(2)` will be:

Options

A. `10^(4) W`
B. `10^(5) W`
C. `10^(6) W`
D. `10^(7) W`

Explanation

To find the total power incident on a rod of dimensions \(10 \, \text{m} \times 10 \, \text{m}\) given the electromagnetic flux of \(10^4 \, \text{W/m}^2\), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values**:
- Intensity (I) = \(10^4 \, \text{W/m}^2\)
- Dimensions of the rod = \(10 \, \text{m} \times 10 \, \text{m}\)

2. **Calculate the Area of the Rod**:
\[ \text{Area} (A) = \text{length} \times \text{width} = 10 \, \text{m} \times 10 \, \text{m} = 100 \, \text{m}^2 \]

3. **Use the Formula for Power**:
The total power (P) incident on the rod can be calculated using the formula:
\[ P = I \times A \]
where \(I\) is the intensity and \(A\) is the area.

4. **Substitute the Values**:
\[ P = 10^4 \, \text{W/m}^2 \times 100 \, \text{m}^2 \]

5. **Perform the Calculation**:
\[ P = 10^4 \times 10^2 = 10^{4+2} = 10^6 \, \text{W} \]

6. **Conclusion**:
The total power incident on the rod is \(10^6 \, \text{W}\).

### Final Answer:
The total power that is incident on the rod is \(10^6 \, \text{W}\).

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