The magnetic field amplitude of an electromagnetic wave is `2 xx 10^(-7)T`. Its' electirc field amplitude if the wave is traveling in free space is

Options

A. `6 V//m`
B. `60 V//m`
C. `10//6 V//m`
D. None of these

Explanation

To find the electric field amplitude of an electromagnetic wave given its magnetic field amplitude, we can use the relationship between the electric field (E) and magnetic field (B) in free space. The formula that relates them is:

\[ E = c \times B \]

where:
- \( E \) is the electric field amplitude,
- \( B \) is the magnetic field amplitude,
- \( c \) is the speed of light in vacuum, approximately \( 3 \times 10^8 \, \text{m/s} \).

### Step-by-Step Solution:

1. **Identify the given values:**
- Magnetic field amplitude, \( B = 2 \times 10^{-7} \, \text{T} \)
- Speed of light, \( c = 3 \times 10^8 \, \text{m/s} \)

2. **Use the formula to find the electric field amplitude:**
\[ E = c \times B \]

3. **Substitute the known values into the equation:**
\[ E = (3 \times 10^8 \, \text{m/s}) \times (2 \times 10^{-7} \, \text{T}) \]

4. **Perform the multiplication:**
\[ E = 3 \times 2 \times 10^{8} \times 10^{-7} \]
\[ E = 6 \times 10^{1} \, \text{V/m} \]

5. **Convert the scientific notation to standard form:**
\[ E = 60 \, \text{V/m} \]

### Final Answer:
The electric field amplitude of the wave is \( 60 \, \text{V/m} \).

---