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if vecE=E(0)cos(kz)cos(omegat)hati then ...

if `vecE=E_(0)cos(kz)cos(omegat)hati` then `vec(B)` for electromagentic wave is

A

The associted magnetic field is given as
`B = 1/(c) (E_(1)hati - E_(2)hatj) cos(kz - omegat)`

B

The associated magnetic field is given as
`B = 1/c (E_(1)hati - E_(2)hatj) cos (kz - omegat)`

C

The given electromagnetic field is circularly polarised.

D

The given electromagnetic wave is plane polarised.

Text Solution

Verified by Experts

The correct Answer is:
D

Here, in electromagnetic wave, the elctric field vector is given as `E = (E_(1)hati + E_(2)hatj) cos (kz - omegat)`
Also E and B perpendicular to each other and the propagation of electromgnetic wave is perpendicular to E as well as B, so the given electromagnetic wave is plane polarised.
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