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The ratio of contributions made by the e...

The ratio of contributions made by the eletric field and magnetic field components to the intensity of an `EM` wave is.

A

(a) `c : 1`

B

(b) `c^(2) : 1`

C

(c) `1 : 1`

D

(d) `sqrt(c) : 1`

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The correct Answer is:
To solve the problem regarding the ratio of contributions made by the electric field and magnetic field components to the intensity of an electromagnetic (EM) wave, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Concept of Intensity in EM Waves**: The intensity (I) of an electromagnetic wave is defined as the power per unit area carried by the wave. It is related to both the electric field (E) and the magnetic field (B) components of the wave. 2. **Relationship Between Electric and Magnetic Fields**: In an electromagnetic wave, the intensity can be expressed in terms of the electric field and magnetic field as follows: \[ I = \frac{1}{2} \epsilon_0 E^2 c = \frac{1}{2} \frac{B^2}{\mu_0} c \] where \( \epsilon_0 \) is the permittivity of free space, \( \mu_0 \) is the permeability of free space, and \( c \) is the speed of light. 3. **Contribution of Electric Field to Intensity**: The contribution to the intensity from the electric field can be calculated as: \[ I_E = \frac{1}{2} \epsilon_0 E^2 c \] 4. **Contribution of Magnetic Field to Intensity**: Similarly, the contribution to the intensity from the magnetic field is: \[ I_B = \frac{1}{2} \frac{B^2}{\mu_0} c \] 5. **Equivalence of Contributions**: For an electromagnetic wave, the electric and magnetic fields are related by the equation \( E = cB \). Therefore, the contributions to the intensity from both fields are equal: \[ I_E = I_B \] 6. **Calculate the Ratio**: Since both contributions are equal, we can express the ratio of the contributions of the electric field to the magnetic field as: \[ \text{Ratio} = \frac{I_E}{I_B} = \frac{1}{1} \] 7. **Conclusion**: Thus, the ratio of contributions made by the electric field and magnetic field components to the intensity of an electromagnetic wave is: \[ \text{Ratio} = 1 : 1 \] ### Final Answer: The ratio of contributions made by the electric field and magnetic field components to the intensity of an EM wave is **1:1**.

To solve the problem regarding the ratio of contributions made by the electric field and magnetic field components to the intensity of an electromagnetic (EM) wave, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Concept of Intensity in EM Waves**: The intensity (I) of an electromagnetic wave is defined as the power per unit area carried by the wave. It is related to both the electric field (E) and the magnetic field (B) components of the wave. 2. **Relationship Between Electric and Magnetic Fields**: ...
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