The energy of gamma `(gamma)` ray photon is `E_(gamma)` and that of an X-rays photon is `E_(X)`. If the visible light photon has an energy of `E_(v)`, then we can say that

Options

A. `E_(X) gt E_(gamma) gt E_(v)`
B. `E_(gamma) gt E_(v) gt E_(X)`
C. `E_(gamma) gt E_(X) gt E_(v)`
D. `E_(X) gt E_(v) gt E_(gamma)`

Explanation

To solve the problem, we need to compare the energies of gamma ray photons, X-ray photons, and visible light photons. The energy of a photon is given by the formula:

\[ E = h \nu \]

where:
- \( E \) is the energy of the photon,
- \( h \) is Planck's constant,
- \( \nu \) (nu) is the frequency of the photon.

### Step-by-step Solution:

1. **Understand the relationship between energy and frequency**:
The energy of a photon is directly proportional to its frequency. This means that as the frequency increases, the energy of the photon also increases.

\[ E \propto \nu \]

2. **Identify the order of frequencies for different types of electromagnetic waves**:
We know the order of electromagnetic waves based on their frequencies:
- Gamma rays have the highest frequency.
- X-rays have a lower frequency than gamma rays but higher than visible light.
- Visible light has the lowest frequency among the three.

Thus, we can express this relationship as:
\[ \nu_{\gamma} > \nu_{X} > \nu_{v} \]

3. **Relate frequencies to energies**:
Since energy is directly proportional to frequency, we can relate the energies of the photons:
- For gamma rays:
\[ E_{\gamma} \propto \nu_{\gamma} \]
- For X-rays:
\[ E_{X} \propto \nu_{X} \]
- For visible light:
\[ E_{v} \propto \nu_{v} \]

4. **Establish the inequalities for energies**:
From the frequency relationships, we can conclude:
\[ E_{\gamma} > E_{X} > E_{v} \]

5. **Final conclusion**:
Therefore, we can say that:
\[ E_{\gamma} > E_{X} > E_{v} \]

### Final Answer:
The correct relationship is:
\[ E_{\gamma} > E_{X} > E_{v} \]