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If c is the velocity of light in free sp...

If c is the velocity of light in free space, the time taken by light to travel a distance x in a medium refractive index `mu` is

A

`(x)/(c)`

B

`(mux)/(c)`

C

`(x)/(muc)`

D

`(c)/(mux)`

Text Solution

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The correct Answer is:
To find the time taken by light to travel a distance \( x \) in a medium with refractive index \( \mu \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Information**: - The speed of light in free space is denoted as \( c \). - The refractive index of the medium is denoted as \( \mu \). - The distance to be traveled by light in the medium is \( x \). 2. **Determine the Speed of Light in the Medium**: - The speed of light in a medium is given by the formula: \[ v = \frac{c}{\mu} \] - Here, \( v \) is the speed of light in the medium, \( c \) is the speed of light in vacuum, and \( \mu \) is the refractive index of the medium. 3. **Use the Formula for Time**: - The time taken \( t \) to travel a distance \( x \) is given by the formula: \[ t = \frac{\text{Distance}}{\text{Speed}} \] - Substituting the values we have: \[ t = \frac{x}{v} \] 4. **Substitute the Speed of Light in the Medium**: - Now, substitute \( v = \frac{c}{\mu} \) into the time formula: \[ t = \frac{x}{\frac{c}{\mu}} \] - This simplifies to: \[ t = \frac{x \cdot \mu}{c} \] 5. **Final Expression**: - Thus, the time taken by light to travel a distance \( x \) in a medium with refractive index \( \mu \) is: \[ t = \frac{\mu x}{c} \] ### Final Answer: The time taken by light to travel a distance \( x \) in a medium with refractive index \( \mu \) is \( \frac{\mu x}{c} \). ---

To find the time taken by light to travel a distance \( x \) in a medium with refractive index \( \mu \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Information**: - The speed of light in free space is denoted as \( c \). - The refractive index of the medium is denoted as \( \mu \). - The distance to be traveled by light in the medium is \( x \). ...
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The lens governing the behavior of the rays namely rectilinear propagation laws of reflection and refraction can be summarised in one fundamental law known as Fermat's principle. According to this principle a ray of light travels from one point to another such that the time taken is at a stationary value (maximum or minimum). if c is the velocity of light in a vacuum the velocity in a medium of refractive index mu is (c)/(mu) hence time taken to travel a distance l is (mul)/(c) if the light passes through a number of media, the total time taken is ((1)/(c))summul or (1)/(c)intmudl if refractive index varies continuously. Now summul is the total path, so that fermat's principle states that the path of a ray is such that the optical path in at a stationary value. this principle is obviously in agreement with the fact that the ray are straight lines i a homogenous isotropic medium. it is found that it also agrees with the classical laws of reflection and refraction. Q. If refractive index of a slab varies as mu=1+x^(2) where x is measured from one end then optical path length of a slab of thickness 1 m is

The lens governing the behavior of the rays namely rectilinear propagation laws of reflection and refraction can be summarised in one fundamental law known as Fermat's principle. According to this principle a ray of light travels from one point to another such that the time taken is at a stationary value (maximum or minimum). if c is the velocity of light in a vacuum the velocity in a medium of refractive index mu is (c)/(mu) hence time taken to travel a distance l is (mul)/(c) if the light passes through a number of media, the total time taken is ((1)/(c))summul or (1)/(c)intmudl if refractive index varies continuously. Now summul is the total path, so that fermat's principle states that the path of a ray is such that the optical path in at a stationary value. this principle is obviously in agreement with the fact that the ray are straight lines i a homogenous isotropic medium. it is found that it also agrees with the classical laws of reflection and refraction. Q. The optical path length followed by ray from point A to B given that laws of refraction are obeyed as shown in figure.

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