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When light rays are incident on a prism ...

When light rays are incident on a prism at an angle of `45^(@)`, the minimum deviation is obtained. If refractive index of the material of prism is `sqrt(2)`, then the angle of prism will be

A

`30^(@)`

B

`75^(@)`

C

`90^(@)`

D

`60^(@)`

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To find the angle of the prism when light rays are incident at an angle of \(45^\circ\) and the refractive index of the material of the prism is \(\sqrt{2}\), we can follow these steps: ### Step 1: Understand the relationship between the angles In the case of minimum deviation, the angle of incidence \(i\) is equal to the angle of emergence \(e\). The relationship is given by: \[ i = \frac{A + \delta_m}{2} \] where \(A\) is the angle of the prism and \(\delta_m\) is the minimum deviation. ### Step 2: Substitute the known values We know that \(i = 45^\circ\). Therefore, we can write: \[ 45^\circ = \frac{A + \delta_m}{2} \] This implies: \[ A + \delta_m = 90^\circ \quad \text{(Equation 1)} \] ### Step 3: Use the refractive index formula The refractive index \(\mu\) is given by: \[ \mu = \frac{\sin(i + \frac{A}{2})}{\sin(\frac{A}{2})} \] Substituting \(\mu = \sqrt{2}\) and \(i = 45^\circ\), we can rewrite the equation as: \[ \sqrt{2} = \frac{\sin(45^\circ + \frac{A}{2})}{\sin(\frac{A}{2})} \] ### Step 4: Calculate \(\sin(45^\circ)\) We know that: \[ \sin(45^\circ) = \frac{1}{\sqrt{2}} \] Thus, the equation becomes: \[ \sqrt{2} = \frac{\frac{1}{\sqrt{2}} + \sin(\frac{A}{2})}{\sin(\frac{A}{2})} \] ### Step 5: Simplify the equation Cross-multiplying gives: \[ \sqrt{2} \sin(\frac{A}{2}) = \frac{1}{\sqrt{2}} + \sin(\frac{A}{2}) \] Rearranging this gives: \[ \sqrt{2} \sin(\frac{A}{2}) - \sin(\frac{A}{2}) = \frac{1}{\sqrt{2}} \] Factoring out \(\sin(\frac{A}{2})\): \[ (\sqrt{2} - 1) \sin(\frac{A}{2}) = \frac{1}{\sqrt{2}} \] ### Step 6: Solve for \(\sin(\frac{A}{2})\) Thus, \[ \sin(\frac{A}{2}) = \frac{1}{\sqrt{2}(\sqrt{2} - 1)} \] To simplify \(\sqrt{2}(\sqrt{2} - 1)\): \[ \sqrt{2}(\sqrt{2} - 1) = 2 - \sqrt{2} \] So, \[ \sin(\frac{A}{2}) = \frac{1}{2 - \sqrt{2}} \] ### Step 7: Find the angle \(\frac{A}{2}\) Using the known values, we can find \(\frac{A}{2}\): \[ \sin(\frac{A}{2}) = \frac{1}{2 - \sqrt{2}} \implies \frac{A}{2} = 30^\circ \] Thus, multiplying by 2 gives: \[ A = 60^\circ \] ### Conclusion The angle of the prism \(A\) is \(60^\circ\).

To find the angle of the prism when light rays are incident at an angle of \(45^\circ\) and the refractive index of the material of the prism is \(\sqrt{2}\), we can follow these steps: ### Step 1: Understand the relationship between the angles In the case of minimum deviation, the angle of incidence \(i\) is equal to the angle of emergence \(e\). The relationship is given by: \[ i = \frac{A + \delta_m}{2} \] where \(A\) is the angle of the prism and \(\delta_m\) is the minimum deviation. ...
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