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When light of wavelength lambda is incid...

When light of wavelength `lambda` is incident on an equilateral prism, kept on its minimum deviation position, it is found that the angle of deviation equals the angle of the prism itself. The refractive index of the material of the prism for the wavelength `lambda` is

A

`sqrt3`

B

`(sqrt3)/2`

C

2

D

`sqrt2`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) Refractive index for prism,
`µ=(sin""((A+delta_(m))/2))/(sin""(A/2))=(sin((60^(@)+60^(@))/2))/(sin""((60^(@))/2))=sqrt3`
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