Home
Class 12
PHYSICS
The focal length of objective and eye le...

The focal length of objective and eye lens of a microscope are `4 cm` and `8 cm` respectively. If the least distance of distinct vision is `24 cm` and object distance is `4.5 cm` from the objective lens, then the magnifying power of the microscope will be

A

18

B

32

C

64

D

20

Text Solution

AI Generated Solution

The correct Answer is:
To find the magnifying power of the microscope, we can follow these steps: ### Step 1: Identify the given values - Focal length of the objective lens, \( f_o = 4 \, \text{cm} \) - Focal length of the eye lens (eyepiece), \( f_e = 8 \, \text{cm} \) - Least distance of distinct vision, \( D = 24 \, \text{cm} \) - Object distance from the objective lens, \( u_o = -4.5 \, \text{cm} \) (negative because object distance is measured against the direction of the incoming light) ### Step 2: Use the lens formula for the objective lens The lens formula is given by: \[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \] For the objective lens, we can rearrange this to find the image distance \( v_o \): \[ \frac{1}{f_o} = \frac{1}{v_o} - \frac{1}{u_o} \] Substituting the known values: \[ \frac{1}{4} = \frac{1}{v_o} - \frac{1}{-4.5} \] This simplifies to: \[ \frac{1}{4} = \frac{1}{v_o} + \frac{1}{4.5} \] ### Step 3: Solve for \( v_o \) To solve for \( v_o \), first find a common denominator for the right side: \[ \frac{1}{v_o} = \frac{1}{4} - \frac{1}{4.5} \] Calculating the right side: \[ \frac{1}{4} = \frac{4.5 - 4}{18} = \frac{0.5}{18} = \frac{1}{36} \] Thus: \[ \frac{1}{v_o} = \frac{1}{36} \] So, \( v_o = 36 \, \text{cm} \). ### Step 4: Calculate the magnifying power \( M \) The magnifying power \( M \) of the microscope is given by: \[ M = \frac{v_o}{u_o} \times \left(1 + \frac{D}{f_e}\right) \] Substituting the known values: \[ M = \frac{36}{-4.5} \times \left(1 + \frac{24}{8}\right) \] Calculating \( \frac{36}{-4.5} \): \[ \frac{36}{-4.5} = -8 \] Now calculate \( 1 + \frac{24}{8} = 1 + 3 = 4 \): \[ M = -8 \times 4 = -32 \] The magnifying power is taken as a positive value: \[ M = 32 \] ### Final Answer The magnifying power of the microscope is \( 32 \). ---

To find the magnifying power of the microscope, we can follow these steps: ### Step 1: Identify the given values - Focal length of the objective lens, \( f_o = 4 \, \text{cm} \) - Focal length of the eye lens (eyepiece), \( f_e = 8 \, \text{cm} \) - Least distance of distinct vision, \( D = 24 \, \text{cm} \) - Object distance from the objective lens, \( u_o = -4.5 \, \text{cm} \) (negative because object distance is measured against the direction of the incoming light) ...
Promotional Banner

Topper's Solved these Questions

  • RAY OPTICS

    DC PANDEY ENGLISH|Exercise Checkpoint 9.7|10 Videos
  • RAY OPTICS

    DC PANDEY ENGLISH|Exercise Exercise|170 Videos
  • RAY OPTICS

    DC PANDEY ENGLISH|Exercise Checkpoint 9.5|10 Videos
  • NUCLEI

    DC PANDEY ENGLISH|Exercise C MADICAL ENTRANCES GALLERY|46 Videos
  • REFLECTION OF LIGHT

    DC PANDEY ENGLISH|Exercise Subjective|9 Videos

Similar Questions

Explore conceptually related problems

The focal lengths of the objective and eye - lens of a microscope are 1cm and 5 cm respectively. If the magnifying power for the relaxed eye is 45 , then the length of the tube is

The focal length of the objective and eye lenses of a microscope are 1.6 cm and 2.5 cm respectively. The distance between the two lenses is 21.7 cm. If the final image is formed at infinity. What is the linear magnification ?

The focal length of objective and eyelens of a astronomical telescope are respectively 20 cm and 5 cm. Final image is formed at least distance of distinct vision. The magnifying power will be

The focal lengths of the objective and eyelens of a microscope are 1.6 cm and 2.5 cm respectively. The distance between the two lenses is 21.7 cm. If the final image is formed at infinity, the distance between the object and the objective lens is :

The focal lengths of the objective and eyelens of a microscope are 1.6 cm and 2.5 cm respectively. The distance between the two lenses is 21.7 cm. If the final image is formed at infinity, the distance between the object and the objective lens is :

Relative difference of focal lengths of objective and eye lens in the microscope and telescope is given as

The focal lengths of the objective and the eyepiece of an astronomical telescope are 20 cm and 5 cm respectively. If the final image is formed at a distance of 30 cm from the eye piece, find the separation between the lenses for distinct vision:

If the focal length of objective and eye lens are 1.2 cm and 3 cm respectively and the object is put 1.25cm away from the objective lens and the final image is formed at infinity. The magnifying power of the microscope is

Least distance of distinct vision is 25 cm . Magnifying power of simple microscope of focal length 5 cm is

The focal length of objective and the eyepiece of a compound microscope are 1cm and 5cm. An object is placed at a distance of 1.1 cm from the objective and if the final image is formed at infinity the magnifying power and distance between the lenses are respectively

DC PANDEY ENGLISH-RAY OPTICS-Checkpoint 9.6
  1. The least distance of distinct vision for a young adult with normal vi...

    Text Solution

    |

  2. When we see an object, image formed on the retina is (i) real (ii) v...

    Text Solution

    |

  3. The focal length of a normal eye lens is about

    Text Solution

    |

  4. An object is placed at a distance u from a simple microscope of focal ...

    Text Solution

    |

  5. Magnifying power of a simple microscope is (when final image is formed...

    Text Solution

    |

  6. In a compound microscope, the intermediate image is

    Text Solution

    |

  7. A compound microscope has two lenses. The magnifying power of one is 5...

    Text Solution

    |

  8. The length of the compound microscope is 14 cm. The magnifying power f...

    Text Solution

    |

  9. If the focal length of objective and eye lens are 1.2 cm and 3 cm resp...

    Text Solution

    |

  10. The focal length of objective and eye lens of a microscope are 4 cm an...

    Text Solution

    |

  11. If the telescope is reversed .i.e., seen seen from the objective side,...

    Text Solution

    |

  12. The aperture of a telescope is made large, because

    Text Solution

    |

  13. In an astronomical telescope, the focal length of the objective lens i...

    Text Solution

    |

  14. The focal lengths of the objective and eye lenses of a telescope are r...

    Text Solution

    |

  15. The number of lenses in a terrestrial telescope is

    Text Solution

    |

  16. Magnifying power of a Galilean telescope is given by

    Text Solution

    |

  17. In Gallilean telescope, the final image formed is

    Text Solution

    |

  18. Reflecting telescope consists of

    Text Solution

    |

  19. Resolving power of a microscope is given by

    Text Solution

    |

  20. The resolving power of a telescope whose lens has a diameter of 1.22 m...

    Text Solution

    |