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Resolving power of a microscope is given...

Resolving power of a microscope is given by

A

`(2musintheta)/(lamda^(2))`

B

`(musintheta)/(lamda)`

C

`(2musintheta)/(lamda)`

D

`(2mucostheta)/(lamda)`

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The correct Answer is:
To find the resolving power of a microscope, we can use the formula: **Resolving Power (R) = (2 * μ * sin(θ)) / λ** Where: - **μ** is the refractive index of the medium between the objective lens and the specimen. - **θ** is the half-angle of the maximum cone of light that can enter the objective lens. - **λ** is the wavelength of the light used for imaging. ### Step-by-Step Solution: 1. **Understand the Concept of Resolving Power**: - Resolving power refers to the ability of a microscope to distinguish between two closely spaced objects. A higher resolving power means better clarity and detail in the image. 2. **Identify the Formula**: - The resolving power of a microscope can be expressed using the formula: \[ R = \frac{2 \mu \sin \theta}{\lambda} \] 3. **Define the Variables**: - **μ (Refractive Index)**: This is a measure of how much the speed of light is reduced inside a medium compared to a vacuum. - **θ (Half-Angle)**: This angle is formed between the optical axis and the line from the lens to the edge of the aperture. It determines how much light can enter the lens. - **λ (Wavelength)**: This is the wavelength of the light used to illuminate the specimen. 4. **Analyze the Options**: - Given the formula, we can analyze the options provided in the question to find which one matches the formula for resolving power. 5. **Select the Correct Option**: - After analyzing, we find that the correct option that matches the formula \( R = \frac{2 \mu \sin \theta}{\lambda} \) is option C. ### Final Answer: The resolving power of a microscope is given by \( R = \frac{2 \mu \sin \theta}{\lambda} \), and the correct option is C.

To find the resolving power of a microscope, we can use the formula: **Resolving Power (R) = (2 * μ * sin(θ)) / λ** Where: - **μ** is the refractive index of the medium between the objective lens and the specimen. - **θ** is the half-angle of the maximum cone of light that can enter the objective lens. - **λ** is the wavelength of the light used for imaging. ...
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DC PANDEY ENGLISH-RAY OPTICS-Checkpoint 9.6
  1. The least distance of distinct vision for a young adult with normal vi...

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  2. When we see an object, image formed on the retina is (i) real (ii) v...

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  3. The focal length of a normal eye lens is about

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  4. An object is placed at a distance u from a simple microscope of focal ...

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  5. Magnifying power of a simple microscope is (when final image is formed...

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  6. In a compound microscope, the intermediate image is

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  7. A compound microscope has two lenses. The magnifying power of one is 5...

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  8. The length of the compound microscope is 14 cm. The magnifying power f...

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  9. If the focal length of objective and eye lens are 1.2 cm and 3 cm resp...

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  10. The focal length of objective and eye lens of a microscope are 4 cm an...

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  11. If the telescope is reversed .i.e., seen seen from the objective side,...

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  12. The aperture of a telescope is made large, because

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  13. In an astronomical telescope, the focal length of the objective lens i...

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  14. The focal lengths of the objective and eye lenses of a telescope are r...

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  15. The number of lenses in a terrestrial telescope is

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  16. Magnifying power of a Galilean telescope is given by

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  17. In Gallilean telescope, the final image formed is

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  18. Reflecting telescope consists of

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  19. Resolving power of a microscope is given by

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  20. The resolving power of a telescope whose lens has a diameter of 1.22 m...

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