Electromagnetic radiation of frequency v, velocity v and wavelength `lambda` in air, enters a glass slab of refractive index μ . The frequency, wavelength and velocity of light in the glass slab will be, respectively

Options

A. `n/mu,lamda/mu,v/mu`
B. `n,lamda/mu,v/mu`
C. `n,lamda,v/mu`
D. `n/mu,lamda/mu,v`

Answer

B

Explanation

(b) In going from one mediumto another frequency remains same but wavelength and velocity decreases with the increase in refractive index i.e., wavelength becomes `lamda'=lamda//mu` and velocity becomes,
`v=c/mu`