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The nearer point of hypermetropic eye i...

The nearer point of hypermetropic eye is `40 cm`. The lens to be used for its correction should have the power

A

`+1.5D`

B

`-1.5D`

C

`+2.5D`

D

`+0.5D`

Text Solution

Verified by Experts

The correct Answer is:
C
(c ) Hypermetropia can be removed by using a convex lens.
Focal length of used lens, f=+d=+40 cm
=+(defected near point)
`therefore` Power of lens=`100/(f(cm))=100/40=2.5D.`
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