The refractive index of the material of prism `sqrt3,` then the angle of minimum deviation of prism is

Options

A. `30^(@)`
B. `45^(@)`
C. `60^(@)`
D. `75^(@)`

Answer

C

Explanation

(c ) Refrctive index of the material of prism,
`mu=(sin((A+delta_(m))/2))/(sin(A/2)`
`rArrsqrt3=mu=(sin((60^(@)+delta_(m))/2))/(sin(60^(@)/2))`
`rArr sqrt3/2=sin(30^(@)+delta_(m)/2)`