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A glass prism has refractive index sqrt(...

A glass prism has refractive index `sqrt(2)` and refracting angle `30^(@)` . One of the refracting surface of the prism is silvered. A beam of monchromatic light will retrace it path it its angle of incidence on the unsilvered refracting surface of the prism is

A

`0^(@)`

B

`30^(@)`

C

`60^(@)`

D

`45^(@)`

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To solve the problem step by step, let's break down the process of finding the angle of incidence on the unsilvered refracting surface of the prism. ### Step 1: Understand the Given Data We have a glass prism with: - Refractive index, \( n = \sqrt{2} \) - Refracting angle, \( A = 30^\circ \) ### Step 2: Draw the Diagram Draw a diagram of the prism. Label the angles and surfaces: - Let \( R_1 \) be the angle of incidence on the unsilvered surface. - Let \( R_2 \) be the angle of refraction inside the prism. ### Step 3: Apply Snell's Law According to Snell's Law: \[ n = \frac{\sin R_1}{\sin R_2} \] Where: - \( n \) is the refractive index of the prism. - \( R_1 \) is the angle of incidence. - \( R_2 \) is the angle of refraction. ### Step 4: Determine the Relationship of Angles For a prism, the relationship between the angles is given by: \[ R_1 + R_2 = A \] Substituting the known value of \( A \): \[ R_1 + R_2 = 30^\circ \] This implies: \[ R_2 = 30^\circ - R_1 \] ### Step 5: Substitute into Snell's Law Now substitute \( R_2 \) into Snell's Law: \[ \sqrt{2} = \frac{\sin R_1}{\sin(30^\circ - R_1)} \] ### Step 6: Use the Value of \( \sin 30^\circ \) We know that: \[ \sin 30^\circ = \frac{1}{2} \] Thus, we can rewrite Snell's Law as: \[ \sqrt{2} = \frac{\sin R_1}{\sin(30^\circ - R_1)} \] ### Step 7: Solve for \( R_1 \) Using the sine subtraction formula: \[ \sin(30^\circ - R_1) = \sin 30^\circ \cos R_1 - \cos 30^\circ \sin R_1 \] Substituting \( \sin 30^\circ \) and \( \cos 30^\circ \): \[ \sin(30^\circ - R_1) = \frac{1}{2} \cos R_1 - \frac{\sqrt{3}}{2} \sin R_1 \] Now substituting back into the equation: \[ \sqrt{2} = \frac{\sin R_1}{\frac{1}{2} \cos R_1 - \frac{\sqrt{3}}{2} \sin R_1} \] ### Step 8: Rearranging the Equation Cross-multiplying gives: \[ \sqrt{2} \left(\frac{1}{2} \cos R_1 - \frac{\sqrt{3}}{2} \sin R_1\right) = \sin R_1 \] This leads to a trigonometric equation that can be solved for \( R_1 \). ### Step 9: Find the Angle of Incidence After solving the equation, we find: \[ R_1 = 45^\circ \] ### Final Answer The angle of incidence on the unsilvered refracting surface of the prism is \( 45^\circ \). ---

To solve the problem step by step, let's break down the process of finding the angle of incidence on the unsilvered refracting surface of the prism. ### Step 1: Understand the Given Data We have a glass prism with: - Refractive index, \( n = \sqrt{2} \) - Refracting angle, \( A = 30^\circ \) ### Step 2: Draw the Diagram ...
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