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A glass prism has a refractive angle of ...

A glass prism has a refractive angle of `90^(@)` and a refractive index of 1.5. A ray is incident at an angle of `30^(@)`. The ray emerges from an adjacent face at an angle of

A

`60^(@)`

B

`30^(@)`

C

`45^(@)`

D

the ray does not emerge

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The correct Answer is:
To solve the problem step by step, we will follow the principles of refraction and apply Snell's law. ### Step 1: Identify Given Values - Refractive angle of the prism (A) = 90° - Refractive index of glass (μ) = 1.5 - Angle of incidence (i) = 30° ### Step 2: Calculate the Critical Angle The critical angle (θc) can be calculated using the formula: \[ \theta_c = \sin^{-1}\left(\frac{1}{\mu}\right) \] Substituting the value of μ: \[ \theta_c = \sin^{-1}\left(\frac{1}{1.5}\right) = \sin^{-1}\left(\frac{2}{3}\right) \approx 41.8° \] ### Step 3: Apply Snell's Law at the First Surface Using Snell's law at the first surface (air to prism): \[ \mu_{\text{air}} \cdot \sin(i) = \mu_{\text{glass}} \cdot \sin(r_1) \] Where: - μ_air = 1 (for air) - i = 30° - μ_glass = 1.5 - r_1 = angle of refraction in the prism Substituting the values: \[ 1 \cdot \sin(30°) = 1.5 \cdot \sin(r_1) \] Since \(\sin(30°) = \frac{1}{2}\): \[ \frac{1}{2} = 1.5 \cdot \sin(r_1) \] \[ \sin(r_1) = \frac{1}{2 \cdot 1.5} = \frac{1}{3} \] Now, calculate \(r_1\): \[ r_1 = \sin^{-1}\left(\frac{1}{3}\right) \approx 19.5° \] ### Step 4: Calculate the Angle of Refraction at the Second Surface The angle of the prism (A) is given by: \[ A = r_1 + r_2 \] Where \(r_2\) is the angle of refraction at the second surface. Given that \(A = 90°\): \[ 90° = 19.5° + r_2 \] Solving for \(r_2\): \[ r_2 = 90° - 19.5° = 70.5° \] ### Step 5: Check if the Ray Emerges Now, we need to check if \(r_2\) is greater than the critical angle: - Critical angle \(θ_c \approx 41.8°\) - \(r_2 = 70.5°\) Since \(r_2\) (70.5°) is greater than the critical angle (41.8°), the ray will not emerge from the second surface. ### Conclusion The ray does not emerge from the adjacent face of the prism. ### Final Answer The ray emerges from the adjacent face at an angle of **not applicable** (it does not emerge). ---

To solve the problem step by step, we will follow the principles of refraction and apply Snell's law. ### Step 1: Identify Given Values - Refractive angle of the prism (A) = 90° - Refractive index of glass (μ) = 1.5 - Angle of incidence (i) = 30° ### Step 2: Calculate the Critical Angle ...
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DC PANDEY ENGLISH-RAY OPTICS-Exercise
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  2. A uniform round object of mass M, radius R and moment of inertia about...

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  3. A glass prism has a refractive angle of 90^(@) and a refractive index ...

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  4. An equilateral prism deviates a ray through 45^(@) for the two angles ...

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  5. The focal length of the objective of a terrestical telescope is 80cm ...

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  6. The length of the tube of a microscope is 10 cm . The focal lengths of...

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  7. The magnifying power of a microscope with an objective of 5 mm focal l...

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  8. A thin plano-convex lens acts like a concave mirror of radius of curva...

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  9. One face of a prism with a refrective angle of 30^@ is coated with sil...

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  10. A convex lens has mean focal length of 20 cm. The dispersive power of ...

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  11. A convex lens of focal length f is placed somewhere in between an obje...

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  12. A square of side 3 cm is placed at a distance of 25 cm from a concave ...

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  13. A plano-convex lens has a maximum thickness of 6 cm. When placed on a ...

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  14. An object is 20 cm away from a concave mirror with focal length 15 cm....

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  15. The dispersive powers of glasses of lenses used in an achromatic pair ...

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  16. A ray falls on a prism ABC(AB=BC) and travels as shown in adjoining fi...

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  17. If the distances of an object and its virtual image from the focus of ...

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  18. A hemispherieal paper weight contains a small flower on its axis of sy...

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  19. A slab of glass, of thickness 6 cm and refractive index mu=1.5 is plac...

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  20. When an object is placed 40cm from a diverging lens, its virtual image...

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