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If c is the velocity of light in free sp...

If c is the velocity of light in free space, then the time taken by light to travel a distance x in a medium refractive index `mu` is

A

`(x)/(2)`

B

`(mux)//(c )`

C

`(x)//(muc)`

D

`(c )//(mux)`

Text Solution

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The correct Answer is:
To find the time taken by light to travel a distance \( x \) in a medium with refractive index \( \mu \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Refractive Index**: The refractive index \( \mu \) of a medium is defined as the ratio of the speed of light in vacuum (or free space) \( c \) to the speed of light in the medium \( v \): \[ \mu = \frac{c}{v} \] 2. **Rearrange the Formula**: From the definition of refractive index, we can express the speed of light in the medium \( v \) as: \[ v = \frac{c}{\mu} \] 3. **Identify the Distance**: We are given that the distance \( x \) is the distance light travels in the medium. 4. **Use the Formula for Time**: The time \( t \) taken to travel a distance \( x \) is given by the formula: \[ t = \frac{\text{Distance}}{\text{Speed}} \] Substituting \( x \) for distance and \( v \) for speed, we have: \[ t = \frac{x}{v} \] 5. **Substitute for Speed**: Now substitute \( v = \frac{c}{\mu} \) into the time formula: \[ t = \frac{x}{\frac{c}{\mu}} = x \cdot \frac{\mu}{c} \] 6. **Final Expression**: Therefore, the time taken by light to travel a distance \( x \) in a medium with refractive index \( \mu \) is: \[ t = \frac{\mu x}{c} \] ### Conclusion: The final answer is: \[ t = \frac{\mu x}{c} \]

To find the time taken by light to travel a distance \( x \) in a medium with refractive index \( \mu \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Refractive Index**: The refractive index \( \mu \) of a medium is defined as the ratio of the speed of light in vacuum (or free space) \( c \) to the speed of light in the medium \( v \): \[ \mu = \frac{c}{v} ...
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The lens governing the behavior of the rays namely rectilinear propagation laws of reflection and refraction can be summarised in one fundamental law known as Fermat's principle. According to this principle a ray of light travels from one point to another such that the time taken is at a stationary value (maximum or minimum). if c is the velocity of light in a vacuum the velocity in a medium of refractive index mu is (c)/(mu) hence time taken to travel a distance l is (mul)/(c) if the light passes through a number of media, the total time taken is ((1)/(c))summul or (1)/(c)intmudl if refractive index varies continuously. Now summul is the total path, so that fermat's principle states that the path of a ray is such that the optical path in at a stationary value. this principle is obviously in agreement with the fact that the ray are straight lines i a homogenous isotropic medium. it is found that it also agrees with the classical laws of reflection and refraction. Q. If refractive index of a slab varies as mu=1+x^(2) where x is measured from one end then optical path length of a slab of thickness 1 m is

The lens governing the behavior of the rays namely rectilinear propagation laws of reflection and refraction can be summarised in one fundamental law known as Fermat's principle. According to this principle a ray of light travels from one point to another such that the time taken is at a stationary value (maximum or minimum). if c is the velocity of light in a vacuum the velocity in a medium of refractive index mu is (c)/(mu) hence time taken to travel a distance l is (mul)/(c) if the light passes through a number of media, the total time taken is ((1)/(c))summul or (1)/(c)intmudl if refractive index varies continuously. Now summul is the total path, so that fermat's principle states that the path of a ray is such that the optical path in at a stationary value. this principle is obviously in agreement with the fact that the ray are straight lines i a homogenous isotropic medium. it is found that it also agrees with the classical laws of reflection and refraction. Q. The optical path length followed by ray from point A to B given that laws of refraction are obeyed as shown in figure.

The lens governing the behavior of the rays namely rectilinear propagation laws of reflection and refraction can be summarised in one fundamental law known as Fermat's principle. According to this principle a ray of light travels from one point to another such that the time taken is at a stationary value (maximum or minimum). if c is the velocity of light in a vacuum the velocity in a medium of refractive index mu is (c)/(mu) hence time taken to travel a distance l is (mul)/(c) if the light passes through a number of media, the total time taken is ((1)/(c))summul or (1)/(c)intmudl if refractive index varies continuously. Now summul is the total path, so that fermat's principle states that the path of a ray is such that the optical path in at a stationary value. this principle is obviously in agreement with the fact that the ray are straight lines i a homogenous isotropic medium. it is found that it also agrees with the classical laws of reflection and refraction. Q. The optical length followed by ray from point A to B given that laws of reflection are obeyed as shown in figure is

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