Home
Class 12
PHYSICS
The diameter of the eye ball of a normal...

The diameter of the eye ball of a normal eye is about 2.5cm. The power of the eye lens varies from

A

9D to 8D

B

40D to 32D

C

44D to 40D

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To determine the power of the eye lens in a normal eye with a diameter of about 2.5 cm, we will analyze two cases: one for distant vision and one for near vision. ### Step-by-Step Solution: **Step 1: Understand the Diameter of the Eyeball** - The diameter of the eyeball is given as 2.5 cm, which is equivalent to 0.025 m. **Step 2: Calculate the Power for Distant Vision** - For distant objects, the object distance (u) is considered to be at infinity (u = ∞). - The image distance (v) is equal to the radius of the eyeball, which is half of the diameter. Therefore, v = 0.025 m. - We use the lens formula: \[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \] Substituting the values: \[ \frac{1}{f} = \frac{1}{0.025} - \frac{1}{\infty} = \frac{1}{0.025} - 0 = \frac{1}{0.025} \] \[ \frac{1}{f} = 40 \text{ m}^{-1} \] Therefore, the focal length (f) is: \[ f = \frac{1}{40} \text{ m} = 0.025 \text{ m} \] **Step 3: Calculate the Power for Distant Vision** - The power (P) of the lens is given by: \[ P = \frac{1}{f} \text{ (in meters)} \] Thus, substituting the focal length: \[ P = 40 \text{ D (diopters)} \] **Step 4: Calculate the Power for Near Vision** - For near vision, the least distance of distinct vision (u) is taken as 25 cm or 0.25 m. - The image distance (v) remains the same at 0.025 m. - Using the lens formula again: \[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \] Substituting the values: \[ \frac{1}{f} = \frac{1}{0.025} - \frac{1}{0.25} \] \[ \frac{1}{f} = 40 - 4 = 36 \text{ m}^{-1} \] Therefore, the focal length (f) is: \[ f = \frac{1}{36} \text{ m} \] **Step 5: Calculate the Power for Near Vision** - The power (P) of the lens for near vision is: \[ P = \frac{1}{f} = 36 \text{ D (diopters)} \] **Step 6: Determine the Range of Power** - The power of the eye lens varies from 40 D (for distant vision) to 44 D (for near vision). ### Final Answer: The power of the eye lens varies from **40 D to 44 D**. ---

To determine the power of the eye lens in a normal eye with a diameter of about 2.5 cm, we will analyze two cases: one for distant vision and one for near vision. ### Step-by-Step Solution: **Step 1: Understand the Diameter of the Eyeball** - The diameter of the eyeball is given as 2.5 cm, which is equivalent to 0.025 m. **Step 2: Calculate the Power for Distant Vision** ...
Promotional Banner

Topper's Solved these Questions

  • RAY OPTICS

    DC PANDEY ENGLISH|Exercise medical entrance special format question|23 Videos
  • NUCLEI

    DC PANDEY ENGLISH|Exercise C MADICAL ENTRANCES GALLERY|46 Videos
  • REFLECTION OF LIGHT

    DC PANDEY ENGLISH|Exercise Subjective|9 Videos

Similar Questions

Explore conceptually related problems

Eye lens is

Eye lens is

The focal length of a normal eye lens is about

The focal length of a normal eye lens is about

Eye lens is formed from

Lens of eyes is derived from

For a normal eye, distance of near point from the eye is.

The shape of eye lens is changed by

The diameter of the pupil of human eye is about 2 mm . Human eye is most sensitive to the wavelength 555 nm . Find the limit of resolution of human eye.

Protein found in eye lens is

DC PANDEY ENGLISH-RAY OPTICS-Medical entrance gallary
  1. The mirror are inclined at angle of 50^(@). The number of images forme...

    Text Solution

    |

  2. If c is the velocity of light in free space, then the time taken by li...

    Text Solution

    |

  3. A beam of light consisting of red, green, and blue colors is incident ...

    Text Solution

    |

  4. A vessel consists of two plane mirrors at right angles as shown in fig...

    Text Solution

    |

  5. For having large magnification power of a compound microsope

    Text Solution

    |

  6. A beam of light is incident on a glass slab (mu = 1.54) in a direction...

    Text Solution

    |

  7. The focal length of lens of refractive index 1.5 in air is 30 cm When ...

    Text Solution

    |

  8. The focal length of a concave mirror is 50 cm. Where an object be plac...

    Text Solution

    |

  9. The diameter of the eye ball of a normal eye is about 2.5cm. The power...

    Text Solution

    |

  10. Two thin lenses, when in contact, produce a combination of power+10 d...

    Text Solution

    |

  11. A ray of light is incident at small angle I on the surface of prism of...

    Text Solution

    |

  12. A concave mirror of focal length f(1) is placed at a distance of d fro...

    Text Solution

    |

  13. The image formed by a convex mirror of focal length 30 cm is a quarter...

    Text Solution

    |

  14. In a compound microscope, the focal length of the objective and the ey...

    Text Solution

    |

  15. A thin convex lens of refractive index 1.5cm has 20cm focal length in ...

    Text Solution

    |

  16. Assertion : The resolving power of a telescope is more if the diameter...

    Text Solution

    |

  17. On the axis of a spherical mirror of focal length f a short linear obj...

    Text Solution

    |

  18. An object is placed at a distance of 10cm form a co-axial combination ...

    Text Solution

    |

  19. White light is incident on the interface of glass and air as shown in ...

    Text Solution

    |

  20. The focal length of the objective of a terrestrial telescope is 80 cm ...

    Text Solution

    |