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Product of velocity and time period of e...

Product of velocity and time period of electron orbiting in nth stable orbit is proportional to

A

`n^(3)`

B

`(1)/(n)`

C

n

D

`n^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze the relationship between the velocity and time period of an electron in the nth stable orbit. ### Step-by-Step Solution: 1. **Understand the Concepts**: - The velocity (v) of an electron in the nth orbit is given by the formula: \[ v \propto \frac{1}{n} \] - The time period (T) of the electron in the nth orbit is given by the formula: \[ T \propto n^3 \] 2. **Express the Product**: - We need to find the product of velocity and time period: \[ v \cdot T \] 3. **Substituting the Proportional Relationships**: - Substitute the expressions for velocity and time period into the product: \[ v \cdot T \propto \left(\frac{1}{n}\right) \cdot (n^3) \] 4. **Simplifying the Expression**: - Simplify the product: \[ v \cdot T \propto \frac{n^3}{n} = n^2 \] 5. **Conclusion**: - Therefore, the product of the velocity and the time period of an electron orbiting in the nth stable orbit is proportional to \( n^2 \). ### Final Answer: The product of velocity and time period of an electron orbiting in the nth stable orbit is proportional to \( n^2 \). Thus, the correct option is option 4: \( n^2 \).

To solve the question, we need to analyze the relationship between the velocity and time period of an electron in the nth stable orbit. ### Step-by-Step Solution: 1. **Understand the Concepts**: - The velocity (v) of an electron in the nth orbit is given by the formula: \[ v \propto \frac{1}{n} ...
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Knowledge Check

  • Total energy of electron in nth stationary orbit of hydrogen atom is

    A
    `(e^2)/(4piepsilon_0r)`
    B
    `(-e^2)/(4piepsilon_0r)`
    C
    `(-e^2)/(8piepsilon_0r)`
    D
    `(e^2)/(8piepsilon_0r)`
  • Total energy of electron in nth stationary orbit of hydrogen atom is

    A
    `(-13.6)/(n)eV`
    B
    `(-13.6)/(n^2)eV`
    C
    `(-136)/(n)eV`
    D
    `(-136)/(n^2)eV`
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