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Kinetic energy of electron in nth orbit ...

Kinetic energy of electron in nth orbit is given by

A

`(Rhc)/(2n^(2))`

B

`(2Rhc)/(n)`

C

`(Rhc)/(n)`

D

`(Rhc)/(n^(2))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the kinetic energy of an electron in the nth orbit, we can follow these steps: ### Step 1: Write the basic formula for kinetic energy The kinetic energy (KE) of an electron in the nth orbit is given by the formula: \[ KE = \frac{2 \pi^2 m e^4}{n^2 h^2} \] where: - \( m \) is the mass of the electron, - \( e \) is the charge of the electron, - \( n \) is the principal quantum number (orbit number), - \( h \) is Planck's constant. ### Step 2: Introduce the Rydberg constant The Rydberg constant \( R \) is defined as: \[ R = \frac{2 \pi^2 m e^4}{c h^3} \] where \( c \) is the speed of light. ### Step 3: Rearrange the kinetic energy formula We want to express the kinetic energy in terms of \( R \), \( h \), and \( c \). To do this, we need to manipulate the original kinetic energy formula. ### Step 4: Modify the kinetic energy formula We can multiply and divide the original kinetic energy formula by \( h \) and \( c \): \[ KE = \frac{2 \pi^2 m e^4}{n^2 h^2} \cdot \frac{h}{h} \cdot \frac{c}{c} \] This gives us: \[ KE = \frac{2 \pi^2 m e^4 h c}{n^2 h^3} \] ### Step 5: Substitute for \( R \) Now, we can substitute \( R \) into the equation: \[ KE = \frac{R h c}{n^2} \] ### Final Result Thus, the kinetic energy of an electron in the nth orbit can be expressed as: \[ KE = \frac{R h c}{n^2} \] ### Conclusion The correct expression for the kinetic energy of an electron in the nth orbit is \( \frac{R h c}{n^2} \). ---
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