Ionisation potential (IP) and ionisation (IE) are related a

Options

A. `IP=(IE)e`
B. `IP=(IE)/(e)`
C. `IE=(IP)/(e^(2))`
D. `IP=(IE)/(e^(2))`

Answer

To find the relationship between ionization potential (IP) and ionization energy (IE), we can follow these steps:

### Step 1: Understand the Definitions
- **Ionization Energy (IE)**: This is the amount of energy required to remove an electron from an atom in its gaseous state.
- **Ionization Potential (IP)**: This is the potential difference (voltage) required to remove an electron from an atom.

### Step 2: Recall the Relationship
We know from electrostatics that energy can be expressed in terms of charge and potential:
\[ \text{Energy} = \text{Charge} \times \text{Potential} \]

### Step 3: Apply the Definitions
In the context of ionization:
- The energy required to remove an electron (IE) can be expressed as:
\[ IE = e \times IP \]
where \( e \) is the charge of the electron.

### Step 4: Rearranging the Equation
From the equation \( IE = e \times IP \), we can rearrange it to express IP in terms of IE:
\[ IP = \frac{IE}{e} \]

### Step 5: Conclusion
Thus, the relationship between ionization potential and ionization energy is:
\[ \text{Ionization Potential (IP)} = \frac{\text{Ionization Energy (IE)}}{e} \]

### Final Answer
The correct option is:
**Ionization potential is equal to ionization energy divided by E (Option B).**

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