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In which of the following transition wil...

In which of the following transition will the wavelength be minimum ?

A

n=5 to n=4

B

n=4 to n=3

C

n=3 to n=2

D

n=2 to n=1

Text Solution

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The correct Answer is:
To determine which transition results in the minimum wavelength, we can use the Rydberg formula for hydrogen-like atoms, which is given by: \[ \frac{1}{\lambda} = RZ^2 \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) \] Where: - \(\lambda\) is the wavelength, - \(R\) is the Rydberg constant, - \(Z\) is the atomic number, - \(n_1\) and \(n_2\) are the principal quantum numbers of the two energy levels involved in the transition, with \(n_2 > n_1\). ### Step-by-Step Solution: 1. **Identify the transitions and their quantum numbers**: - Option A: \(n_1 = 2\), \(n_2 = 5\) - Option B: \(n_1 = 3\), \(n_2 = 4\) - Option C: \(n_1 = 2\), \(n_2 = 3\) - Option D: \(n_1 = 1\), \(n_2 = 2\) 2. **Calculate the wavelength for each transition**: - **Option A**: Transition from \(n = 5\) to \(n = 2\) \[ \frac{1}{\lambda_A} = R \left( \frac{1}{2^2} - \frac{1}{5^2} \right) = R \left( \frac{1}{4} - \frac{1}{25} \right) = R \left( \frac{25 - 4}{100} \right) = R \left( \frac{21}{100} \right) \] \[ \lambda_A = \frac{100}{21R} \] - **Option B**: Transition from \(n = 4\) to \(n = 3\) \[ \frac{1}{\lambda_B} = R \left( \frac{1}{3^2} - \frac{1}{4^2} \right) = R \left( \frac{1}{9} - \frac{1}{16} \right) = R \left( \frac{16 - 9}{144} \right) = R \left( \frac{7}{144} \right) \] \[ \lambda_B = \frac{144}{7R} \] - **Option C**: Transition from \(n = 3\) to \(n = 2\) \[ \frac{1}{\lambda_C} = R \left( \frac{1}{2^2} - \frac{1}{3^2} \right) = R \left( \frac{1}{4} - \frac{1}{9} \right) = R \left( \frac{9 - 4}{36} \right) = R \left( \frac{5}{36} \right) \] \[ \lambda_C = \frac{36}{5R} \] - **Option D**: Transition from \(n = 2\) to \(n = 1\) \[ \frac{1}{\lambda_D} = R \left( \frac{1}{1^2} - \frac{1}{2^2} \right) = R \left( 1 - \frac{1}{4} \right) = R \left( \frac{3}{4} \right) \] \[ \lambda_D = \frac{4}{3R} \] 3. **Compare the wavelengths**: - \(\lambda_A = \frac{100}{21R}\) - \(\lambda_B = \frac{144}{7R}\) - \(\lambda_C = \frac{36}{5R}\) - \(\lambda_D = \frac{4}{3R}\) 4. **Determine the minimum wavelength**: - To find the minimum wavelength, we need to compare the values obtained: - \(\lambda_A \approx 4.76\) - \(\lambda_B \approx 20.57\) - \(\lambda_C \approx 7.2\) - \(\lambda_D \approx 1.33\) From the calculations, we find that the minimum wavelength occurs for **Option D**: Transition from \(n = 2\) to \(n = 1\). ### Final Answer: The transition with the minimum wavelength is from \(n = 2\) to \(n = 1\).

To determine which transition results in the minimum wavelength, we can use the Rydberg formula for hydrogen-like atoms, which is given by: \[ \frac{1}{\lambda} = RZ^2 \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) \] Where: - \(\lambda\) is the wavelength, ...
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