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Ionization energy of a hydrogen-like ion...

Ionization energy of a hydrogen-like ion A is greater than that of another hydrogen like ion B . Let r, u, E and L represent the radius of the orbit , speed of the electron , total energy of the electron and angular momentum of the electron respectively (for the same n ). In ground state :

A

`r_(A) gt r_(B)`

B

`u_(A) gt u_(B)`

C

`E_(A) lt E_(B)`

D

`L_(A) gt L_(B)`

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The correct Answer is:
To analyze the given problem about the hydrogen-like ions A and B, we need to understand the relationships between ionization energy, radius, speed, total energy, and angular momentum in the context of quantum mechanics. ### Step-by-Step Solution: 1. **Understanding Ionization Energy**: - The ionization energy (IE) of a hydrogen-like ion is given by the formula: \[ IE = 13.6 \, \text{eV} \times Z^2 \] - Since it is stated that the ionization energy of ion A is greater than that of ion B, we can conclude: \[ IE_A > IE_B \implies Z_A^2 > Z_B^2 \implies Z_A > Z_B \] - Thus, the atomic number \( Z \) of ion A is greater than that of ion B. 2. **Angular Momentum (L)**: - The angular momentum of an electron in a hydrogen-like atom is quantized and given by: \[ L = n \frac{h}{2\pi} \] - For both ions A and B in the ground state (n=1), the angular momentum will be the same: \[ L_A = L_B \] - Therefore, angular momentum does not depend on the atomic number \( Z \) for the same principal quantum number. 3. **Radius of the Orbit (r)**: - The radius of the electron's orbit in a hydrogen-like atom is given by: \[ r = \frac{n^2}{Z} \cdot a_0 \] - Since \( Z_A > Z_B \), the radius for ion A will be less than that for ion B: \[ r_A < r_B \] 4. **Speed of the Electron (u)**: - The speed of the electron in a hydrogen-like atom is given by: \[ u = \frac{Z e^2}{4 \pi \epsilon_0 h} \cdot \frac{1}{n} \] - Since \( Z_A > Z_B \), the speed of the electron in ion A will be greater than that in ion B: \[ u_A > u_B \] 5. **Total Energy (E)**: - The total energy of the electron in a hydrogen-like atom is given by: \[ E = -\frac{Z^2 \cdot 13.6 \, \text{eV}}{n^2} \] - Since \( Z_A > Z_B \), the total energy for ion A will be more negative than that for ion B: \[ E_A < E_B \] ### Summary of Relationships: - **Angular Momentum**: \( L_A = L_B \) - **Radius**: \( r_A < r_B \) - **Speed**: \( u_A > u_B \) - **Total Energy**: \( E_A < E_B \)
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