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In Rutherford scattering experiment, wha...

In Rutherford scattering experiment, wha will be the ratio of impact parameter for scattering angles `theta_(1)=90^(@) and theta_(2)=120^(@)`

A

1

B

`sqrt(2)`

C

2

D

`sqrt(3)`

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AI Generated Solution

The correct Answer is:
To solve the problem of finding the ratio of the impact parameters for the scattering angles \( \theta_1 = 90^\circ \) and \( \theta_2 = 120^\circ \) in the Rutherford scattering experiment, we can follow these steps: ### Step 1: Understand the relationship between impact parameter and scattering angle The impact parameter \( B \) in the Rutherford scattering experiment is proportional to the cotangent of half the scattering angle. Mathematically, this can be expressed as: \[ B \propto \cot\left(\frac{\theta}{2}\right) \] ### Step 2: Calculate the impact parameter for \( \theta_1 = 90^\circ \) For \( \theta_1 = 90^\circ \): \[ B_1 \propto \cot\left(\frac{90^\circ}{2}\right) = \cot(45^\circ) \] Since \( \cot(45^\circ) = 1 \): \[ B_1 \propto 1 \] ### Step 3: Calculate the impact parameter for \( \theta_2 = 120^\circ \) For \( \theta_2 = 120^\circ \): \[ B_2 \propto \cot\left(\frac{120^\circ}{2}\right) = \cot(60^\circ) \] Since \( \cot(60^\circ) = \frac{1}{\sqrt{3}} \): \[ B_2 \propto \frac{1}{\sqrt{3}} \] ### Step 4: Find the ratio of the impact parameters Now, we need to find the ratio \( \frac{B_1}{B_2} \): \[ \frac{B_1}{B_2} = \frac{1}{\frac{1}{\sqrt{3}}} = \sqrt{3} \] ### Conclusion The ratio of the impact parameters for the scattering angles \( \theta_1 = 90^\circ \) and \( \theta_2 = 120^\circ \) is: \[ \frac{B_1}{B_2} = \sqrt{3} \] ### Final Answer Thus, the answer is \( \sqrt{3} \). ---

To solve the problem of finding the ratio of the impact parameters for the scattering angles \( \theta_1 = 90^\circ \) and \( \theta_2 = 120^\circ \) in the Rutherford scattering experiment, we can follow these steps: ### Step 1: Understand the relationship between impact parameter and scattering angle The impact parameter \( B \) in the Rutherford scattering experiment is proportional to the cotangent of half the scattering angle. Mathematically, this can be expressed as: \[ B \propto \cot\left(\frac{\theta}{2}\right) \] ...
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