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An electron makes a transition from orbi...

An electron makes a transition from orbit n=4 to the orbit n=2 of a hydrogen atom. The wave number of the emitted radiations (R=Rydberg's constant) will be

A

`(16)/(3R)`

B

`(16)/(5R)`

C

`(5R)/(16)`

D

`(3R)/(16)`

Text Solution

Verified by Experts

The correct Answer is:
A

Wavelength is give by
`" " (1)/(lambda)=R((1)/n_(2)^(2)-(1)/(n_(2)^(2)))rArr(1)/(lambda)=R [(1)/((2)^(2))-(1)/((4)^(2))]`
`rArr" " (1)/(lambda)=R((1)/(4)-(1)/(16))rArr(1)/(lambda)=R((4-1)/(16))`
`rArr" " (1)/(lambda)=(3R)/(16)rArrlambda=(16)/(3R)`
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