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de-Broglie wavelength of an electron in ...

de-Broglie wavelength of an electron in the nth Bohr orbit is `lambda_(n)` and the angular momentum is `J_(n)` then

A

`J_(n)proplambda_(n)`

B

`lambda_(n)prop(1)/(J_(n))`

C

`lambda_(n)propJ_(n)^(2)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A

`lambda (h)/(p)=(h)/(mv)`
or `" " lambda prop (1)/(v)`
`:. " " lambda_(n)prop n rArr J_(n)=n(h)/(2pi) i.e., J_(n) prop n`
Hence, `" " lambda_(n)propJ_(n)`
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