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The radius of hydrogen atom in its groun...

The radius of hydrogen atom in its ground state is `5.3xx10^(-11)m`. After collision with an electron it is found to have a radius of `21.2xx10^(-11)m`. What is the principal quantum number n of the final state of atom ?

A

n=4

B

n=2

C

n=16

D

n=3

Text Solution

Verified by Experts

The correct Answer is:
B
`rpropn^(2)i.e.,(""^rf)/(r_(i))=((n_(f))/(n_(i)))^(2)`
`rArr " " (21.2xx2xx10^(-11))/(5.3xx10^(-11))=((n)/(1))^(2)rArrn^(2)=4rArrn=2`
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DC PANDEY ENGLISH-ATOMS-Taking it together
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